(3x/x^2+2x)-(1/2)

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Solution for (3x/x^2+2x)-(1/2) equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+(3*x)/(x^2)-(1/2) = 0

2*x+(3*x)/(x^2)-1/2 = 0

2*x^1+3*x^-1-1/2*x^0 = 0

(2*x^2-1/2*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-1/2*x^1+3*x^0) = 0

x^1

2*x^2+(-1/2)*x+3 = 0

2*x^2+(-1/2)*x+3 = 0

DELTA = (-1/2)^2-(2*3*4)

DELTA = -95/4

DELTA < 0

x in { }

x belongs to the empty set

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